I have four baseboard electric heaters with a total rating of 4,190W in a single room controlled by an existing King single-pole thermostat. The number of watts = area x 10. Hello.

Do I need to add the wattage of both units to confirm it is under 3800 W? If I am reading you correctly, I would not be able to replace that thermostat with a Mysa? It is due to the fact that not all houses are alike. ft. x 10 = 1200 watts). If the heat up time is decreased to 30 min, then twice the amounts of Watts are required. The best assessment of the heating needs of a house will be done by the addition of the results for each room. Am I compatable for a mysa? I have 5 rooms with baseboard heat and each room has its own analog thermostat, but they all go to the same breaker. Multiply the heater length by 225 to estimate wattage. Technical Calculations for Industrial Heating, Calculating Wattage for Industrial Heaters, Quick estimates for thermal wattage requirements, Watt density and operating temperatures guidelines for various materials, The type of material or fluid to be heated, The mass of the material (in lbs) to be heated, The desired time to reach set temperature, Steel: (66 lbs, spec. Each is 8.3A, so 1992W each= 3984W total.

If the wattage is not listed on the label, you can determine the wattage of each heater with this simple formula: I’m updating a cottage that I haven’t yet put internet at- the options for that are actually limited, so I need to put some thought into which type to choose. The number of wires, amperage, and wattage are all very important when it comes to radiant heat. In North America we still can find BTU/hr being used as a measure of power in heating. In order to calculate the heating required we must consider the size and volume of the house, orientation, size and number of windows, type of insulation found in the walls and roof, etc. This result is valid for houses containing rooms whose ceilings are 8 feet high. It could read that it only works for single types – like thermostats for just baseboard or just forced fan.

Hey, Bill. (example: freezing protection) For most water heating applications we do recommand the use of a mechanical stirring mechanism. Hi! It should work, but this use case is a little on the rare side. If you wish to determine the efficiency of your space heater… We strongly recommend you do not exceed this wattage. It would be best to contact our support team at support@getmysa.com to help you further. Ultimate Guide to Efficient Baseboard Heaters, Why Your Programmable Thermostats Cost You Money Every Month, Ask An Engineer: PID Control and the Triac, How To Install Nest/Ecobee With Electric Baseboard Heaters, Why Airbnb Owners Need a Smart Thermostat, How To Calculate The Total Wattage Of Your In-Floor Heating System, Many homeowners wonder how they can calculate the current total wattage of their baseboard heaters in each room. heat = .095) = 206 watts; If the heat up time is decreased to 30 min, then twice the amounts of Watts are required. Unfortunately, it will not replace the other thermostats.” Electric baseboard heaters on average need 225 watts per foot. We can figure the same thing in the case of walls with oversized windows. © Stelpro, Inc. 2020. Watts calculation. A 10 ft. x 12 ft. room, for example, requires a 1200 watt space heater (120 sq.

The thermostats are 240v high voltage system. Then, use graph below to be sure that the watt density is within allowable limits.

Also,during a natural power outage or power surge due to weather,will the thermostat reset to a different degree if I’m not home,does it have memory or what will it do?

Hello, I have 2 8 ft Baseboard heaters connected together, 3600 W but how do I know how many Amps? If you’re thinking about purchasing. That's the tricky part because it depends on pressure and temperature of the air. In most cases, the Power Factor is a standard of 1 unit, but there are always exceptions to this rule. Single pole vs double pole: what’s the difference? Calculate Watt Density and Fit - After the wattage for each heater has been established, the watt density and fit must be calculated. The efficiency of the heating method (conduction, convection, radiation) as well as the heater type will have a significant impact on power requirement and therefor operating costs. If you suspect that the walls or ceilings have insulation deficiencies, feel free to add a few percentage points to the calculation. If we rely solely on electric baseboards as a heating source, they are usually installed at the base of windows in order to get the best distribution of heat. Can you confirm it will work for my baseboard AND fan forced heater thermostats? There’s also a 3,800-watt total capacity limitation for 208VAC systems. Will it restart by itself? In order to use smart features and scheduling you will need WiFi. If it’s a standard baseboard heater it is unlikely that it will surpass our limits. Will mysa work as an ordinary thermostat without WiFi? For example a 3/4" x 10" heater rated 1200 watts has a watt … Will this work? Would like to install on a 240V circuit with 2 baseboard heaters. Thanks Brad. Conversely, if a room is windowed and well oriented to the sun we can stay with the regular calculation. Thank you for your help. If the air is compressed to 50 PSI, the inlet temp is 500 degF, and the temperature needs to be increased to 700 degF, then you'll need 32 kW. Do you have a smart thermostat compatible with that?
I was going to install 5 of these mysa units to replace the old king units. Hey, Chip!

The specs of the thermostat is 3800 Watts @ 240VAC, what would be the specs of the thermostat (& load capacity) when the line voltage is 208VAC? I have thermostats in every room,so I’m guessing that there is no radient heat through the ceilings in the hall & bathrooms or I wouldn’t have the baseboards. The number of watts = area x height x 1.25. My new Mysa has been connected for 7 hours now, and the room is cold, baseboards barely heating (set to 23 but stays at 19), all within specs ( 3 BB for 3000w total) and wifi working great… what is the possible issue? Looks like you’re slightly over the limit. We’ve made great strides in ensuring that happens with most setups! In this case, do not hesitate to divide the total watts required by the number of the windows for each room. How to Calculate Total Wattage of Baseboard Heaters, But now you're asking: The formula to convert BTU to kW is the following: P(kW)= P(BTU/hr)/ 3412.14. Depending on application, (example: heat loss in fluid tank), other factors need to be taken into consideration. How do I check wattage on the forced fan? Water is best heated with immersion heaters or circulation heaters, custom heating systems or flexible heaters for wrap around drums or tanks. In general, the power required by electrical heating is calculated in watts. What happens if it’s a bit higher, like 4000w. We don’t have a product that supports such an amperage. When I go through the compatibility test, select multiple heat sources – electric baseboard / electric fan – forced and check all the parameters I get this response: It would be useful to know the magic formula that would give us exactly the amount of heat required to heat a particular room or entire house. Mysa could possibly be compatible with the above system if the system meets the required specifications, which you can find on http://www.getmysa.com. Thanks! For a room 20 feet by 20 feet, we obtain 400 sq.ft., multiplied by 10 to give 4000 watts. heat = .12) = 232 watts, Al : (23 lbs, spec. (standard air is 70 degF @ 14 PSI) SCFM stands for standard cubic feet per minute and Delta T = exit temperature minus inlet temperature in degrees. I hope that helps! There should be a sticker on the fan-forced heater somewhere denoting what Wattage it is rated for. My electrician says I need 30amps for my two long baseboard heaters that are currently on their OG 1968 Art Deco thermostat! If not, you can google the model number! Will it works? The power P in watts (W) is equal to the voltage V in volts (V) times the current I in amps (A): The power P in watts (W) is equal to the squared voltage V in volts (V) divided by the resistance R in ohms (Ω): The power P in watts …


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